Remembering this simple formula will save your troubles.
M1L1 = M2L2
M stands for MOLARITY.
L stands for LITERS
Example:
You have 2.00L of 15.4M HCL and you need 500.0 mL of 3.00M HCl, how much of the original (HCl) concentration do you ned, and how much H20 do you need? Answer in mL
Now plug in the numbers into the formula.
15.4M HCl x L1 = 3.00M HCl x 0.500L
Solve what side has most info (right side in this case)
15.4M HCl x L1 = 1.5 mol HCl
Like math we're trying to find L1
1.5 mol HCl = 100 mL
1.5M
Then find the water needed.
Simple subtract L2 qith L1.
0.500L - 0.100L = 0.400L or 400mL of water is needed
Quick video on how to dilute :)
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